The sum of consecutive integers 1,2,3, ..., n is given by the formula 1/2n (n+1). How many consecutive integers, starting with 1, must be added to get the sum of 1081

Question

Mathematics

Karlee Larsen

Today, 03:16

The sum of consecutive integers 1,2,3, ..., n is given by the formula 1/2n (n+1). How many consecutive integers, starting with 1, must be added to get the sum of 1081

+3

Answers (1)

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Gracie Lindsey · Answer 1

1/2 * n * (n+1) = 1081

distribute

1/2 n^2 + 1/2n - 1081=0

factor out 1/2

1/2 (n^2 + n - 2162) = 0

multiply each side by 2

(n^2 + n - 2162) = 0

factor

(n-46) (n+47) = 0

n=46, n=-47

n cannot be negative

n=46

Answer 46