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17 December, 02:56

The prisoner's dilemma. The release of two out of three prisoners has been announced. but their identity is kept secret. One of the prisoners considers asking a friendly guard to tell him who is the prisoner other than himself that will be released, but hesitates based on the following rationale: at the prisoner's present state of knowledge, the probability of being released is 2/3, but after he knows the answer, the probability of being released will become 1 / 2, since there will be two prisoners (including himself) whose fate is unknown and exactly one of the two will be released. What is wrong with this line of reasoning

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  1. 17 December, 05:29
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    we conclude that there are no changes in the conditional probability of being released

    Step-by-step explanation:

    With the given exercise we know that we nominate as A, B and C as the probability that 3 prisoners are released and A has a particular factor which is the friendly guard

    the probability of one being released is 1/3 by the following pairs: AB, BC, AC

    we know that the guard tells B that he is released

    P (B) = P (A and B are being released and the guard has to tell him that B is released) + P (B and C are being released and the guard can tell that one of B or C is being released)

    Let's get the following equation

    = P (AB) * P (B | AB) + P (BC) * P (B | BC)

    we replace the data defining that

    = (1/3) * (1) + (1/3) * (1/2) = 1/2

    we focus on finding the result

    therefore P (A is released since B is released) = P (A | B) = P (AB) / P (B) = (1/3) / (1/2) = 2/3

    we conclude that there are no changes in the conditional probability of being released.
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