Solve the system of equations.

2x + 3y = 6

x + 4y = - 2

x = 0, y = 2

x = 6, y = - 2

x = 2, y = - 1

x = 3, y = 0

2*0+3*2 = 6

0+6=6

6=6

so x=0, y=2 is right for first equation

2x+3y=6

X+4y=-2

You have to make the x have the same numbers, so you have to multiply by the opposite. This means; 1 (2x+3y=6)

2 (x+4y=-2)

2x+3y=6 2x+8y=-4

Now subtract inorder to have y only.

2x-2x=0 3y - (+8) = -5y 6 - (-4) = 10

-5y=10

-y=2

Y=-2

To find x, substitute y in any of the first equations given

2x+3 (-2) = 6

2x-6=6

2x=6+6

2x=12

X=6

Y=-2 X=6

To see if I am correct, substitute x and y in any of the first equations

X+4y=-2

6+4 (-2) = -2

6-8=-2

-2=-2

Substitute in the other equation also to be sure.