Write the quadratic equation y = (x) 2-6x-7 in vertex form

y = (x-3) ^2 - 16

Step-by-step explanation:

y = x^2 - 6x-7

We need to complete the square

b = - 6

b/2 = - 6/2 = - 3

(b/2) ^2 = (-3) ^2 = 9

Add 9 then subtract 9 to balance the equation

y = x^2 - 6x + 9 - 9 - 7

y = (x^2 - 6x+9) - 16

The terms in parentheses is (x-b/2) ^2

y = (x-3) ^2 - 16

This is in vertex form

The vertex is (3,-16)

Answer:y = (x-3) ^2 - 16