Solve the equation 16y (2-y) + (4y-5) 2=0

16y (2-y) + (4y-5) (2) = 0

Step 1: Simplify both sides of the equation.

-16y2+40y-10=0

Step 2: Use quadratic formula with a=-16, b=40, c=-10.

y=-b±√b2-4ac2a

y = - (40) ±√ (40) 2-4 (-16) (-10) 2 (-16)

y=-40±√960-32

y=54+-14√15 or y=54+14√15

Answer:

y=54+-14√15 or y=54+14√15