Last season Ellen and Janet together won 32 tennis matches Ellen won 6 more than then Janet How many more matches did Ellen win

19 matches which is 6 more than Janet's

Step-by-step explanation:

Let the matches won by Ellen be A and Janet be B

Given they both won 32 matches

That's

A + B = 32

And Ellen won 6 more than Janet

That's

A = 6 + B

So we now have two equations

1. A + B = 32

2. A = 6 + B

Substitute B + 6 for A in the first equation

We have

A + B = 32

6 + B + B = 32

6 + 2B = 32

Subtract 6 from both sides

6 - 6 + 2B = 32 - 6

2B = 26

Divide both sides by 2

2B/2 = 26/2

B = 13

Recall

A = 6 + B

Therefore

A = 6 + 13

A = 19

Ellen won 19 matches which is 6 more than Janet's

T = J + E

T = J + (J + 6)

T = 32

32 = 13 + (13 + 6)

32 = 13 + 19

32 = 32

Ellen won 19 matches.