Find the center and the radius of the circle with the equation:x^2+6x+y^2+4y+12=0

The center is at (-3, - 2) and the radius = 1.

Step-by-step explanation:

We can do this by converting the given equation to standard form.

x^2+6x+y^2+4y+12=0

x^2+6x+y^2+4y = - 12

Completing the square on the x and y terms:

(x + 3) ^2 - 9 + (y + 2) ^2 - 4 = - 12

(x + 3) ^2 + (y + 2) ^2 = - 12 + 9 + 4

(x + 3) ^2 + (y + 2) ^2 = 1

So the center is (-3, - 2) and the radius = 1.