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11 March, 18:27

Solve x + y + z = - 6

-2x - 2y - 2z = 12

5x + 5y + 5z = - 30

Solve x + y = 6

y + z = 0

x + y - z = 4

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Answers (1)
  1. 11 March, 19:48
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    here we have given three system of linear equations.

    x+y+z=-6

    -2x-2y-2z=12

    5x+5y+5x=-30.

    here three unknowns will have same value x=y=z.

    the x+y+z=-6

    x+x+x=-6=3x=-6, x=-2

    we know that x=y=z.

    then x=-2 y=-2 and z=-2.

    for part b we have three equation x+y=6

    y+z=0

    x+y-z=0

    we need to use substitution method.

    in second equation we have y+z=0 it mean y=-z

    we need to plug y=-z in any one of the equation to find other value.

    in first equation we have x+y=6 it becomes x-z=6

    then in third equation we have x+y-z=4 we will rewrite this as x-z+y=4

    we know that x-z=6

    so 6+y=4

    y=-2

    y+z=0 = -2+z=0

    z=2

    we know x+y=6

    x + (-2) = 6=x=8.

    x=8 y=-2 z=2
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