Solve (x + 1 - 3).

{all real numbers}

1 < x < 4

x

Question

Mathematics

Chance Fry

13 June, 13:34

Solve (x + 1 - 3).

{all real numbers}

1 < x < 4

x

+2

Answers (1)

Know the Answer?

Kyle Branch · Answer 1

The answer is: 1
Step-by-step explanation:

We have to find the common region for the inequalities:

x+1-3; where x is a real number.

i. e we need to find the region of (x + 1 - 3).

let us find the region for : x+1<5

⇒ x<5-1 (subtracting both side by 1)

⇒ x<4

the region is (-∞,4)

in set-builder definition form it could be written as: - ∞
now calculating the region for the second inequality: x-4>-3

⇒ x>-3+4 (Adding 4 on both the sides of the inequality)

⇒ x>1

Hence, the region is (1,∞)

in set-builder definition form it could be written as: 1
So, the common region in (-∞,4) and (1,∞) i. e. (-∞,4) ∩ (1,∞) = (1,4).

Hence the answer is: 1

Solve (x + 1 - 3).{all real numbers}1 < x < 4x

Solve (x + 1 - 3).

{all real numbers}

1 < x < 4

x