What are possible solutions for 2X + 7 less than equal to 3X - 5

We are given inequality:

2x + 7 less than equal to 3x - 5.

2x + 7 ≤ 3x - 5

Subtracting 7 from both sides, we get

2x + 7-7 ≤ 3x - 5-7

2x ≤ 3x - 12.

Subtracting 3x from both sides, we get

2x-3x ≤ 3x - 3x - 12

-x ≤ - 12.

Dividing both sides by - 1. we get

x ≥ 12.

Note: When we multiply or divide be a negative number the inequality sign get flip.

Therefore, x is greater than or equal to 12.