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11 February, 19:06

How do I find the horizontal asymptote of h (x) = x+6/x^2-64?

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  1. 11 February, 19:45
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    I assume the equation described is:

    (x + 6) / (x^2 - 64)

    You can compare the degree of the numerator and denominator in a function that takes the form of this type of rational equation.

    Here are the three rules

    #1 (Correct Answer) : When the degree of the numerator is smaller then the denominator the horizontal asymptote is y = 0

    #2 If the degree of the numerator and denominator is the same, then you take the leading coefficient of the numerator (n) and denominator (d) to create the answer y = n / d in this equations case it would be 1 / 1 since variables technically have an invisible 1 in front of them since anything multiplied by 1 is its self, 1x = x

    #3 When the degree of the numerator is greater then the degree of the denominator then this means that it does not have a horizontal asymptote.

    Again the final answer is that the horizontal asymptote is y = 0
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