The sum of two consecutive integers is 4,031. What are the integers?

They are 2015 and 2016.

divide 4031 by 2, and get rid of the decimal:

You will get 2015.

2015+2015 = 4030

2015+2016=4031

First represent your 2 consecutive integers as follows.

X ⇒ first integer

X + 1 ⇒ second integer

Since their sum is 4,031, our equation reads x + (x + 1) = 4,031.

Simplifying on the left side, we get 2x + 1 = 4,031.

Now subtract 1 from both sides to get 2x = 4,030.

Now divide both sides by 2 to find that x = 2,015.

If x ix 2,015, then x + 1 will be 2,015 + 1 or 2,016.

So our 2 consecutive integers are 2,015 and 2,016.