Ask Question
19 May, 05:45

A sparkling-water distributor wants to make up 200 gal of sparkling water to sell for $ 5.00 per gallon. She wishes to mix three grades of water selling for $10 .00, $1 .00, and $4.50 per gallon, respectively. She must use twice as much of the $4.50 water as the $ 1.00 comma water. How many gallons of each should she use?

+3
Answers (2)
  1. 19 May, 06:59
    0
    x=50

    y=50

    z=100

    Step-by-step explanation:

    Let x = $10

    y = $1

    z = $4.5

    2y=z

    5 * 200 = 1000 Dollars wanted

    1000 = 10x + y + 4.5z

    variables represent number of gallons of each type

    1000 = 10x + y + 4.5 (2y) sub z for y

    x=50

    y=50

    z=100
  2. 19 May, 08:53
    0
    The answer will be D
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “A sparkling-water distributor wants to make up 200 gal of sparkling water to sell for $ 5.00 per gallon. She wishes to mix three grades of ...” in 📘 Mathematics if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers