The claim is that the white blood cell counts of adult females are normally distributed, with a standard deviation equal to 1.61. A random sample of 45 adult females has white blood cell counts with a mean of 7.47 and a standard deviation of 2.15. Find the value of the test statistic.

78.46

Step-by-step explanation:

Given that

Pop. Standard deviation = 1.61

Sample standard deviation = 2.15

Sample mean = 7.47

Sample size = 45

Recall that

Test stat for chi square

= (n - 1) (sample standard dev/pop standard dev) ^2

= 45 - 1 (2.15/1.61) ^2

= 44 (1.3354) ^2

= 44 * 1.78329

= 78.46

The value of the test statistics is 79.00

Step-by-step explanation:

The expression used for calculating the test statistics for a chi square test if variance is given by;

T = (n-1) {s/σ}² where

n is the sample size

s is the sample standard deviation

σ is the population standard deviation

Given n = 45

s = 2.15

σ = 1.61

T = (45-1) (2.15/1.61) ²

T = 44 (1.34) ²

T = 79.00