What is the probability that Bo, Colleen, Jeff, and Rohini win the first, second, third, and fourth prizes, respectively, in a drawing if 48 people enter a contest and winning more than one prize is allowed

1/4669920

Step-by-step explanation:

First if all, when repetition is mot allowed, we use Permutation to get the number of possible outcomes as follows;

P (n, r) = n! / (n - r) !

Now, the order is important since the first, second, third and fourth prizes are different.

Thus, we need to define the Permutation.

We need to select 4 winners of the 48 people.

Thus, n = 48 and r = 4

Thus;

P (48,4) = 48! / (48 - 4) !

P (48,4) = 4669920

Now, probability is the number of favourable outcomes divided by number of possible outcomes

Thus,

Probability = 1/4669920