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29 November, 10:37

If f (x) = x^3-x, what is the average rate of change of f (x) over the interval [1,5]?

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  1. 29 November, 13:03
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    30

    Step-by-step explanation:

    Average rate of change=Δf (x) / Δx = [f (x2) - f (x1]/[x2-x1]

    Δf (x) / Δx = [f (5) - f (1]/[5-1]

    f (5) = 5³-5=120

    f (1) = 1³-1=0

    Δf (x) / Δx = [120-0]/[5-1]=120/4=30
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