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4 October, 07:20

A flying objects height in the sky can be represented by the equation d=30+vt+4t^2 where d is the height in feet, v is the velocity in feet per second, and t is the time in seconds. How long has the flying object been traveling if it has velocity of 8 feet per second and has risen to a height of 126 feet? A: 4 seconds

B: 6 seconds

C: 8 seconds

D: 16 seconds

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  1. 4 October, 10:40
    0
    4 s

    Step-by-step explanation:

    d = 30 + vt + 4t²

    v = 8 ft/s; d = 126 ft

    126 = 30 + 8t + 4t² Subtract 126 from each side

    4t² + 8t - 96 = 0 Divide each side by 4

    t² + 2t - 16 = 0 Factor the equation

    (t + 6) (t - 4) = 0

    t + 6 = 0 t - 4 = 0

    t = - 6 t = 4

    We reject the negative time, so t = 4.

    The object has been travelling for 4 s.
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