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28 November, 12:27

Which equation has the solutions x = 1 plus-or-minus StartRoot 5 EndRoot?

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  1. 28 November, 16:13
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    The quadratic equation is x^2-2x-4

    Step-by-step explanation:

    We want to know the equation that has the solution below;

    x = 1 ± √5

    This means x = 1 + √5 or 1 - √5

    The equation would thus be;

    (x-1-√5) (x-1 + √5)

    = x (x-1 + √5) - 1 (x-1 + √5) - √5 (x-1 + √5)

    Opening the brackets we have;

    x^2-x + √5x-x + 1 - √5-√5x + √5-5

    collecting like terms we have;

    x^2-2x+1-5

    = x^2-2x-4
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