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23 August, 08:59

3,9,15 what is the 36th term

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  1. 23 August, 10:52
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    firstly, we have to find the difference

    the diff is 6

    we apply the concept diN+0

    Di is difference

    N is n

    0 is first term - difference

    first term is 3

    diff is 6

    3-6 = - 3

    nth term is 6n-3

    then, we just substitute which is n is the 36th term

    : 6 (36) - 3 = 213
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