the perimeter of a rectangular field is (16a+8b-6c) units and one of its side is (5a+3b-4c) find the other side

3a+b+c

The perimeter is two times one side (to account for the opposite) and two times the adjacent side. So if the sides would be x and y, the perimeter would be 2*x + 2*y.

So, knowing that the sum is 16a+8b-6c, if we subtract the given side 5a+3b-4c from this, what remains is two times the "other" side:

16a+8b-6c - 2 * (5a+3b-4c) =

16a+8b-6c - 10a-6b+8c =

6a+2b+2c

half of that is

(6a+2b+2c) / 2 = 3a+b+c