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23 December, 01:52

Which is a correct two column proof. Given <4 and

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  1. 23 December, 03:07
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    The initial statement is: QS = SU (1)

    QR = TU (2)

    We have to probe that: RS = ST

    Take the expression (1) : QS = SU

    We multiply both sides by R (QS) R = (SU) R

    But (QS) R = S (QR) Then: S (QR) = (SU) R (3)

    From the expression (2) : QR = TU. Then, substituting it in to expression (3):

    S (TU) = (SU) R (4)

    But S (TU) = (ST) U and (SU) R = (RS) U

    Then, the expression (4) can be re-written as:

    (ST) U = (RS) U

    Eliminating U from both sides you have: (ST) = (RS) The proof is done.
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