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3 December, 23:40

What are the x intercepts of the following equaition? y=x^2+5x+4

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  1. 4 December, 00:38
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    x=-4 x=-1

    Step-by-step explanation:

    y=x^2+5x+4

    To find the x intercepts, set the equation equal to zero

    0 = x^2+5x+4

    Factor the equation

    What 2 numbers multiply to 4 and add to 5

    4*1 = 4

    4+1 = 5

    0 = (x+4) (x+1)

    Using the zero product property

    x+4 = 0 x+1=0

    x=-4 x=-1

    These are the x intercepts
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