Robbie was given $80 to spend at the Fair. His admission to the park costs $15.50 and each ride cost $5. He anticipates the cost of food at the fair will be $25. What is the maximum number of rides he can take at the Fair?

7 or 8

Step-by-step explanation:

Robbie was given $80.

His admission costs $15.50

80 - 15.50 = $64.50

He anticipates the cost of food at the fair will be $25.

64.50 - 25 = $39.50

What is the maximum number of rides he can take at the Fair?

(Total $ after admission and cost of food / ride cost)

$39.50 / $5 = 7.9

Answer: the maximum number of rides he can take at the Fair is 7.

Step-by-step explanation:

Let x represent the number of rides that he wants to take at the Fair.

His admission to the park costs $15.50 and each ride cost $5. This means that the cost of x rides would be expressed as

15.5 + 5x

He anticipates the cost of food at the Fair will be $25. This means that the expression for the total amount that he would spend is

15.5 + 5x + 25

If Robbie was given $80 to spend at the Fair, it means that

15.5 + 5x + 25 = 80

5x + 40.5 = 80

5x = 80 - 40.5 =

5x = 39.5

x = 39.5/5

x = 7.9

Since the number of rides cannot be a fraction, then the maximum number of rides he can take at the Fair is 7