Ask Question
4 April, 11:43

amber invested 25000 at 2% for 3 years compound simiannually. Find future value at the end of 3 years?

+4
Answers (2)
  1. 4 April, 12:24
    0
    Use the compound interest formula:

    A = P (1+r/n) ^ (nt). Here, P = $25000, r = 0.02, t = 3 and n = 2.

    Then:

    A = $25000 (1 + 0.02/2) ^ (3*2)

    = $25000 (1.01) ^6

    = $26538.00 (future value at the end of 3 years)
  2. 4 April, 12:25
    0
    First you use the compound interest formula which is: A = P (1+r/n) ^ (nt).

    Plug in the number in this case being P = $25000, r = 0.02, t = 3 and n = 2.

    A = $25000 (1 + 0.02/2) ^ (3*2)

    = $25000 (1.01) ^6

    = $26538.00 (future value at the end of 3 years)
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “amber invested 25000 at 2% for 3 years compound simiannually. Find future value at the end of 3 years? ...” in 📘 Mathematics if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers