The base of a rectangular solid is 4ft. long and 3ft. wide. What is the volume of the solid if its diagonal is sqrt of 41 ft.?

The diagonal of the figure forms a right angle triangle with the diagonal of the base and the height of the figure.

Diagonal of base = √ (3² + 4²)

= 5ft

Diagonal of solid² = Diagonal of base² + height²

height = √ ((√41) ² + 5²)

height = 8.12 feet

Volume = width x length x height

Volume = 3 x 4 x 8.12

= 97.44 cubic feet