A garage is scheduled to have a temporary gravel floor until the homeowner has a he funds necessary to poor concrete floor. Washed gravel is 105 pounds per cubic foot. F the inside dimension of the garage if the L35' / W. 22' and 18" deep. How much the gravel will be required for the floor. Round the answer to the next whole ton? Ok

Question

Mathematics

Santiago Bryant

8 November, 17:54

A garage is scheduled to have a temporary gravel floor until the homeowner has a he funds necessary to poor concrete floor. Washed gravel is 105 pounds per cubic foot. F the inside dimension of the garage if the L35' / W. 22' and 18" deep. How much the gravel will be required for the floor. Round the answer to the next whole ton? Ok

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Answers (1)

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Phoenix Miles · Answer 1

842 pounds

Step-by-step explanation:

Given in the question,

dimension of the garage is 35'' by 22'' by 18''

Total gravel need to be filled

L x W x H

35'' x 22'' x 18''

13860 in³

1 in³ = 0.000578704 ft³

13860 in³ = 13860 * 0.000578704 ft³

= 8.0208 ft³

Given that gravel is 105 pounds per cubic foot

so,

105 x 8.0208

842.18793

≈ 842 pounds