Find two consecutive integers such that the smaller integer decreased by nine equals three times the larger integer.

Let the first integer be x, since they are consecutive, the other will be x + 1

Following the question;

x-9 = 3 (x + 1)

x - 9 = 3x + 3

3x-x = - 3-9

2x = - 12

x = - 12/2

x = - 6 and x + 1 = - 6 + 1 = - 5

The integers are - 6 and - 5

The integers are - 5 and - 6