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21 February, 11:31

Find two consecutive integers such that the smaller integer decreased by nine equals three times the larger integer.

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Answers (2)
  1. 21 February, 12:58
    0
    Let the first integer be x, since they are consecutive, the other will be x + 1

    Following the question;

    x-9 = 3 (x + 1)

    x - 9 = 3x + 3

    3x-x = - 3-9

    2x = - 12

    x = - 12/2

    x = - 6 and x + 1 = - 6 + 1 = - 5

    The integers are - 6 and - 5
  2. 21 February, 15:23
    0
    The integers are - 5 and - 6
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