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17 August, 07:56

A used car dealer sells SUVs and cars. Of all the vehicles, 70% are cars. Of all the vehicles, 10% are black SUVs. What is the probability that an SUV chosen at random is black? Round your answer to the nearest tenth of a percent.

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  1. 17 August, 09:29
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    Answer: 0.3

    Step-by-step explanation:

    From the question,

    A used car dealer sells SUVs and cars. Of all the vehicles, 70% are cars. Since 70% are cars, SUV will be (100% - 70%) = 30%. Of all the vehicles, 10% are black SUVs. To calculate the probability than an SUV chosen is black goes thus:

    P (A|B) = P (A and B) / P (B)

    P (SUV | black) = P (SUV and black) / P (suv)

    P (suv | black) = 10% / 30%

    P (suv | black) = 0.1/0.3

    P (suv | black) = 0.3
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