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29 June, 17:28

How do you solve y^2=12y-36

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  1. 29 June, 21:19
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    We move all the expressions to one side. We would have:

    y^2-12y+36=0

    (y-6) (y-6) = 0 (Because when you multiply (y-6) (y-6) you get y^2-12y+36)

    The only possible answer would be y=6
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