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8 August, 23:41

At a storage company, items are stored in containers that have a base of 4 1 5 yds by 1 1 3 yds. If there is a 3 * 3 array of these containers with no space between them, what is the area covered by the containers?

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  1. 9 August, 02:35
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    Area = 50.4 yd²

    Step-by-step explanation:

    Given

    Base dimension of container = 4⅕ by 1⅓ yd

    Array: 3 * 3 containers without space

    Required

    Area covered by the containers

    First, it'll be assumed that the container has a rectangular base.

    The dimension of the base is measured out as follows:

    Length, L = 4⅕ yd

    Width, W = 1⅓ yd

    Note that this can also be interchanged.

    Next, is to calculate the area of 1 container ...

    Area = 4⅕ yd * 1⅓ yd

    Convert mixed fractions to improper fraction

    Area = 21/5 * 4/3 yd²

    Area = 84/15 yd²

    Area = 28/5 yd²

    Area = 5.6 yd²

    Next, is to calculate the area of the 3 by 3 containers.

    Given that the container formed a 3 by 3 array;

    This means that there 3 * 3 containers

    3 * 3 = 9 containers.

    Area of the 9 containers = 9 * Area of 1 container.

    Area = 9 * 5.6 yd²

    Area = 50.4 yd²

    Hence, the area covered by the containers is 50.4 yd²
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