Tim wants to build a rectangular fence around his yard. He has 42

feet of fencing. If he wants the length to be twice the width, what is the largest possible length? Write an equation and solve.

A) 4w+4=42; l=18

B) 4w+8=42; l=16

C) 6w-42; l=7

D) 6w=42; l=14

Question

Mathematics

Pittman

25 February, 08:23

Tim wants to build a rectangular fence around his yard. He has 42

feet of fencing. If he wants the length to be twice the width, what is the largest possible length? Write an equation and solve.

A) 4w+4=42; l=18

B) 4w+8=42; l=16

C) 6w-42; l=7

D) 6w=42; l=14

+1

Answers (2)

Know the Answer?

Yandel Townsend · Answer 1

I think its D

Keshawn Stewart · Answer 2

D) 6w = 42; l=14

Step-by-step explanation:

since we know,

perimeter of a rectangle = 2 (length + width)

therefore,

=> 2 (l + w) = 42

but we know, l = 2w

=> 2 (3w) = 42

=> 6w = 42,

Tim wants to build a rectangular fence around his yard. He has 42feet of fencing. If he wants the length to be twice the width, what is the largest possible length? Write an equation and solve.A) 4w+4=42; l=18B) 4w+8=42; l=16C) 6w-42; l=7D) 6w=42; l=14

Tim wants to build a rectangular fence around his yard. He has 42

feet of fencing. If he wants the length to be twice the width, what is the largest possible length? Write an equation and solve.

A) 4w+4=42; l=18

B) 4w+8=42; l=16

C) 6w-42; l=7

D) 6w=42; l=14