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15 January, 04:06

A manufacturer wants to double the volume of a 3 in.*2 in.*6 in. 3 i n. * 2 i n. * 6 i n. box, while using as little extra cardboard as possible. Which statement is true?

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  1. 15 January, 07:26
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    Answer: 2 inch dimension will give smallest increase.

    Step-by-step explanation:

    Length = 3 in

    width = 2 in

    height = 6 in

    Extra cardboard means to find surface area

    on doubling the length

    length = 6 In

    width = 2 In

    Height = 6In

    Surface area for the above dimensions = 2 [ 6x2+2x6+6x6] = 120 sq in

    On doubling the width

    length = 3 in

    width = 4 in

    Height = 6 inch

    Surface area for the above dimensions = 2 [ 3x4+4x6+6x3] = 2[54] = 108 sq inches

    On doubling height

    Length = 3 in

    width = 2 in

    Height = 12 in

    Surface area for above dimensions = 2 [ 3x2+2x12+12x3] = 2[6+24+36] = 132 sq inch

    On doubling width surface area is minimum.
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