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1 September, 20:39

A curve is described by the following parametric equations:

x=3+t

y=t^2-4

A. The curve is a parabola with a vertex at (3,-4) and is traced from left to right for increasing values of t.

B. The curve is a parabola with a vertex at (3,-4) and is traced from right to left for increasing values of t.

C. The curve is a parabola with a vertex at (-3,4) and is traced from left to right for increasing values of t.

D. The curve is a parabola with a vertex at (-3,4) and is traced from right to left for increasing values of t.

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Answers (1)
  1. 1 September, 23:03
    0
    Correct option: A

    Step-by-step explanation:

    To find the equation of the curve related to x and y, we can isolate t in the first equation and then use the value of t in the second equation:

    x = 3 + t - > t = x - 3

    y = t^2 - 4 - > y = (x-3) ^2 - 4 = x^2 - 6x + 9 - 4 = x^2 - 6x + 5

    Looking at the curve, we know it is a parabola. To find its vertex, we can use the formula:

    x_vertex = - b / 2a

    x_vertex = 6 / 2 = 3

    To find y_vertex, we use x = x_vertex in the equation:

    y_vertex = 3^2 - 6*3 + 5 = - 4

    So the vertex is (3, - 4)

    Looking at the first equation, we can see that an increase in t causes an increase in x, so we know that the parabola is traced from left to right for increasing values of t.

    Correct option: A
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