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28 December, 10:27

Is the function even, odd or neither?

f (x) = |x| + 1

Your answer:

Even

Odd

Neither

+1
Answers (2)
  1. 28 December, 13:22
    0
    Answer: Even

    Step-by-step explanation:

    This graph has been translated up by one unit but is still symmetrical about the y axis.

    A simple proof would be to check if f (x) = f (-x). If it does, then it is even.

    To check for an odd function, check if f (-x) = - f (x). If it does, then it is even.

    To check for neither, f (-x) will not equal - f (x)
  2. 28 December, 13:36
    0
    Answer: Even

    Explanation
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