How to solve x-2=3 (x-4)

x - 2 = 3 (x - 4)

Distribute 3 inside the parentheses.

x - 2 = 3x - 12

Add 2 to both sides.

x = 3x - 10

Subtract 3x from both sides.

-2x = - 10

Divide both sides by - 2.

x = 5

x-2 = 3 (x-4)

First we should simplify "3 (x-4) " ... 3x-12

Now we have : x-2 = 3x-12

Then we should isolate the x and leave it on one side by itself, to do this we can subtract x from both sides and add the 12 to both, doing this we get:

10=2x

Then we should divide the 2 to both sides and we end up with:

x=5