Ask Question
4 September, 02:34

Solve using the elimination method.

2r - 5s = - 14

5r + 2s = 23

+3
Answers (1)
  1. 4 September, 04:23
    0
    Since you can't multiply either equation by a single number to make the r's or s's cancel out you need to multiply both equations.

    I'm going to make the r's cancel out by multiplying the top equation by 5 and the bottom by - 2

    5 (2r - 5s = - 14)

    -2 (5r + 2s = 23)

    Once I multiply I have

    10r - 25s = - 70

    -10r - 4s = - 46

    Now add straight down, and you are left with:

    -29s = - 116

    To get s by itself now you need to divide both sides by - 29

    -29s = - 116

    -29 - 29

    And your result is s = 4

    To find the value of r, substitute s = 4 into one of the original equations and solve for r.

    2r - 5 (4) = - 14

    2r - 20 = - 14

    + 20 + 20

    2r = 6

    so r = 3

    So your solution is s=4 and r = 3
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “Solve using the elimination method. 2r - 5s = - 14 5r + 2s = 23 ...” in 📘 Mathematics if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers