if N is a positive integer, and twice the square of n is the same as four times and, what is the value of n?

First translate into an equation. Then solve

N=non-negative integers.

2 (n^2) = 4n. Divide both sides of = by 2

n^2 = 2n subtract 2n from both sides

n^2 - 2n = 0. Factor

n (n - 2) = 0. Solve factor = 0.

N = 0. N-2 = 0

+2. + 2

N = 2

So 0 & 2 are both answers