The sum of four consecutive even integers is at least 244. Find the least possible value of the first integer.

x + x + 1 + x + 2 + x + 3 > = 244

=" 4x + 6 > = 244

=" 4x > = 238

=" x > = 238/4 > = 59.5

since x is an integer ... least value of x is 60

The least possible even integer is 58

Step-by-step explanation:

Let's let x be an even integer. The next three would be shown by x+2, x+4 x+6 so now we can add all these to equal 244. Shown with an equation would look like:

x + x+2 + x+4 + x+6 = 244

Combine like terms will be:

4x+12=244

Subtract 12 from both sides we will get

4x=232

Now Divide each side by 4

x=58

So now put x in the above equation and we get the numbers

x=58,

x+2 = 60

X+4 = 62

x+6 = 64

The least one is 58