Ask Question
13 October, 14:33

The average price of a two-bedroom apartment in the uptown area of a prominent American city during the real estate boom from 1994 to 2004 can be approximated by p (t) = 0.15e0.10t million dollars (0 ≤ t ≤ 10) where t is time in years (t = 0 represents 1994). What was the average price of a two-bedroom apartment in this uptown area in 2002, and how fast was it increasing? (Round your answers to two significant digits.) HINT [See Quick Example 3.]

+2
Answers (1)
  1. 13 October, 15:30
    0
    p (t) = 0.19e0.10t

    =>p' (t) = 0.19e0.10t (0.10*1)

    =>p' (t) = 0.019e0.10t

    t = 0 represents 1994

    for 2002, t=2002-1994 = 8

    in 2002

    average price = p (8)

    =>average price = 0.19e0.10*8

    =>average price = 0.422853 ... million

    rate of increase = p' (8)

    =>rate of increase = 0.019e0.10*8

    =>rate of increase = 0.0422853 ... million per year

    p (8) = $ 0.42 million

    p' (8) = $ 0.042 million per year
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “The average price of a two-bedroom apartment in the uptown area of a prominent American city during the real estate boom from 1994 to 2004 ...” in 📘 Mathematics if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers