A first number plus twice a second is 13. Twice the first number plus the second totals 14. Find the numbers. The smaller of the two numbers is.

X=1st y=2nd

x+2y=13 2x+y=14

First set one of the equations equal to x or y

x=13-2y now plug this in the other equation for x

2 (13-2y) + y=14 distribute

26-4y+y=14 - ->26-3y=14

get the y alone

-3y=14-26 - -> - 3y=-12

divide by - 3 on both sides

y=4

now plug 4 into one of the original equations to find x

x+2 (4) = 13 - ->x+8=13 - -> x=13-8

x=5