Evaluate 10 sigma n=2 - 2n-3

-135

Step-by-step explanation:

The summation notation of 10∑n=2 - 2n-3.

We can find the values by substituting n into - 2n-3.

Let's begin where n = 2

-2 (2) - 3 = - 7

-2 (3) - 3 = - 9

-2 (4) - 3 = - 11

-2 (5) - 3 = - 13

-2 (6) - 3 = - 15

-2 (7) - 3 = - 17

-2 (8) - 3 = - 19

-2 (9) - 3 = - 21

-2 (10) - 3 = - 23

This gives us:

-7 + - 9 + - 11 + - 13 + - 15 + - 17 + - 19 + - 21 + - 23 = - 135