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17 November, 14:18

Which of the following are solutions to the equation below?

Check all that apply.

x^2 + 4x + 4 = 12

A. x = - √2+12

B. x = √2+12

C. x = - 2√3-2

D. x = - 2√3+2

E. x = 2√3-2

F. x = 2√3+2

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Answers (1)
  1. 17 November, 16:34
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    There are several ways in which we could answer this question. My choice is to actually solve the given quadratic equation, x^2 + 4x + 4 = 12.

    Note that x^2 + 4x + 4 is a perfect square. Thus,

    x^2 + 4x + 4 = 12 is the same as (x+2) ^2 = 12, so that

    x+2 = plus or minus √3*√4, or plus or minus 2√3.

    Thus, the two real, unequal roots are

    x = - 2 + 2√3 and x = - 2 - 2√3. These correspond to answer choices C and E.
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