Cara is playing a number game where she has two tiles for each number 0 to 9. A tile is chosen at random. How many favorable outcomes are there for choosing a multiple of 3?

Question

Mathematics

Kyan Wagner

9 August, 09:50

Cara is playing a number game where she has two tiles for each number 0 to 9. A tile is chosen at random. How many favorable outcomes are there for choosing a multiple of 3?

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Kasen Brennan · Answer 1

If a card is chosen at random, there are 3 possible favorable outcomes for choosing a multiple of 3.

Step-by-step explanation:

The number of possible numbers on the tile are:

0, 1, 2, 3, 4, 5, 6, 7, 8 and 9.

Now, the chosen tile can have any of the ten options mentioned above.

The favorable outcomes are 3, 6 and 9 as they are the multiple of 3.

So, the number of possible favorable outcomes = 3 ways

Hence, if a card is chosen at random, there are 3 possible favorable outcomes for choosing a multiple of 3.