The width of a rectangle is 2 inches more than three times the length. If the perimeter is 124 inches, what are the dimensions of the rectangle? (find both length and width)

Let x=L.

Then let 3x+2=W

Giving you 124 = (x) + (x) + (3x+2) + (3x+2)

Then simplify and solve.

124=8x+4

124-4=8x

120=8x

120/8=x

15=x

Then put that value back into the original equations to find the dimensions.

x=L

15=Length

and

3x+2=W

3 (15) + 2=W

77=Width