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16 March, 23:43

What is the 9th term of the geometric sequence 5 - 25 125

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  1. 17 March, 02:27
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    Step-by-step explanation:

    hello:

    the n-ieme term is : An=A1*r^ (n-1)

    A1 the first term r : the common ratio

    in this exercice : A1 = 5 r = 125/-25=-25/5 = - 5 n = 9

    A9=5 * (-5) ^ (9-1) = 5*5^8 = 5^9 because : ((-5) ^ (8) = 5^8)
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