Given log4^3 = 0.792 and log4^ 21=2.196 what is log4^7

1.404

1.739

2.773

2.988

Question

Mathematics

Bradley Moreno

14 June, 22:14

Given log4^3 = 0.792 and log4^ 21=2.196 what is log4^7

1.404

1.739

2.773

2.988

+1

Answers (1)

Know the Answer?

Kaiden Nunez · Answer 1

We have to find log4^7 if we know that log4^3 = 0.792 and log4^21 = 2.196.

We already know that:

log (x/y) = log x - log y

log4^21 = log4^ (21 / 3) =

= log4^ 21 - log4^ 7 = 2.196 - 0.797 = 1.404

Answer:

A) 1.404

Given log4^3 = 0.792 and log4^ 21=2.196 what is log4^71.4041.7392.7732.988

Given log4^3 = 0.792 and log4^ 21=2.196 what is log4^7

1.404

1.739

2.773

2.988