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29 May, 14:58

What is the additive inverse of the complex number 13-2

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  1. 29 May, 17:03
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    -13 + j*2

    Step-by-step explanation:

    The additive inverse of a complex number x = a + j*b

    is a number y, such that

    x + y = 0

    This means that

    y = - x = - a - j*b

    Therefore

    The additive inverse of 13 - j*2 is equal to

    - (13 - j*2) = - 13 + j*2
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