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6 August, 13:53

Determine whether the given linear equations are parallel, perpendicular, or neither. 5x - 3y = - 6 3x + 5y = - 20

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  1. 6 August, 16:51
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    We need to put these equations into y=mx+b format.

    5x-3y=-6

    -3y=-5x-6. (take 5x from both sides)

    y=5/3 x + 2 (divide both sides by - 3)

    The slope is 5/3

    3x+5y=-20

    5y = - 3x - 20 (subtract 3x from both sides)

    y=-3/5x - 4 (divide both sides by 5)

    The slope is - 3/5

    The slopes of perpendicular lines are the opposite (+/-) reciprocal. We have 5/3 and - 3/5. This shows they are perpendicular.
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