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24 November, 23:48

How do you put y=-3 (x-4) ^2-10 in standard form?

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Answers (2)
  1. 25 November, 02:11
    0
    y=-3x^2 + 24x - 58

    Step-by-step explanation:

    You first distribute the - 3 by multiplying it to x and - 4. Then just add the exponent.
  2. 25 November, 02:42
    0
    y = - 3x² + 24x - 58

    Step-by-step explanation:

    You distribute out the root and simply it.

    y = - 3 (x-4) ² - 10

    y = - 3 (x² - 8x + 16) - 10

    y = - 3x² + 24x - 48 - 10

    y = - 3x² + 24x - 58
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