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7 June, 01:56

Find the fifth roots of 243 (cos 300° + i sin 300°).

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  1. 7 June, 02:54
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    In looking for the fifth roots, we will use De Moivre's theorem.

    The formula for this problem is z^5 = 243 (cos 300 degress + i sin 300 degrees)

    Where you'll also need the following dа ta:

    300/5 = 60

    360/5 = 72

    - you'll input these two after the cos and i sin (60+k*72) where k = 0,1,2,3,4

    solution:

    z^5 = 243 (cos 300 degrees + i sin 300 degrees)

    z = 243^1/5 (cos 300 degrees + i sin 300 degrees)

    z = 3 (cos (60 + k*72) degrees) + (i sin (60 + k*72) degrees)

    so the following are the roots:

    3 (cos 60 degrees + i sin 60 degrees)

    3 (cos 132 degrees + i sin 132 degrees)

    3 (cos 204 degrees + i sin 204 degrees)

    3 (cos 276 degrees + i sin 276 degrees)

    3 (cos 348 degrees + i sin 348 degrees)
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